Author Topic: A financial riddle  (Read 1282 times)

Ron Scott

  • Handlebar Stache
  • *****
  • Posts: 1999
A financial riddle
« on: December 31, 2023, 12:06:22 PM »
3 guys decide to go fishing.

First stop is the beer dock because of course it is. They grab a case, the kid at the counter says $30, they each put down $10 and off they go.

The dock owner goes over to the kid and says that case is on sale this week for $25. Go give those guys $5 back.

The kid grabs 5 singles and heads to the door. But he starts thinking. 3 guys/5 dollars? That doesn't go! So he pockets 2 bucks and gives each guy a single. They're happy. He's happy.

BUT WAIT...SOMETHING's WRONG

The guys paid $30--$10 each. When they got the dollar back from the kid, they only paid $9 each.

$9 X 3 = $27. The kid pocketed $2.

$27 + $2 = $29... 


What happened to the other dollar???

NotJen

  • Handlebar Stache
  • *****
  • Posts: 1812
  • Location: USA
Re: A financial riddle
« Reply #1 on: December 31, 2023, 12:52:05 PM »
The actual math is $27-$2 = $25.  The 27+2 means nothing.

The beer cost $25.

9x3 = $27 paid by the guys.

Kid stole $2.

Beer seller ended up with the correct $25.


Villanelle

  • Walrus Stache
  • *******
  • Posts: 7364
Re: A financial riddle
« Reply #3 on: December 31, 2023, 02:34:32 PM »
They got $25 in beer and $3 in cash, for a total of $28.  That's what the men walked away with--$28 in cash and goods.  They should have walked out with $30, but the kid stole $2 from them.  How that theft was distributed among the men is irrelevant. 

To look at it another way, imagine that instead of $30 ($10 pp) they paid $27 ($9pp).  Then the kid hands them the beer and send them away, stealing their $2 in change. Those numbers make perfect sense. This is exactly the same, except in your scenario, they initially overpaid by $5 instead of by $2 ($30/$27) then got $3 back before the kid stole $2. 


 

Wow, a phone plan for fifteen bucks!